Who would win in a fight?
The guy might have the physical advantage, but he has to face two girls at the same time. Who would win this fight?
2 Average girls | 25 | |
1 Average guy | 18 |
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The guy might have the physical advantage, but he has to face two girls at the same time. Who would win this fight?
2 Average girls | 25 | |
1 Average guy | 18 |
If we use the equation s((x^2)/2+x/2), we can calculate the way it would work in a simulation by finding the arbitrary strength values of each of the two groups. Even if we assumed that the females were at half the strength of the males, using this method, they would win. f=1((2^2)/2+2/2)=3 ; m=2((1^2)/2+1/2)=2 ; 3>2, so the females would win with about one-third of their health remaining.
Yeah, if it's just a question of raw strength.
Btw that equation looks genius and I don't understand it.
It's not that complex at all. "s" is the relative strength of each individual unit in a group (it has to be greater than 1), and "x" is the number of units in that group. If I make the equation easier to read, it looks like this:
..(..(x^2).......x....)
x.|..-----..+..-----..|
..(....2.........2....)
So, if I wanted to find, say a comparison of two units with 1.5 relative strength, versus three units with 1 relative strength, the equation would look like this:
....(...(2^2).........2....)
1.5.|..--------..+..-----..|
....(.....2...........2....)
Versus:
..(..(3^2).......3....)
1.|..-----..+..-----..|
..(....2.........2....)
So, it's 4.5 AS vs 6 AS. 4.5<6, so the three units with 1 Relative Strength would win with 1/3 of their combined health left (meaning that, in the most common use for this equation, two of them would be dead).
Interest stuff, Clunk. Did this originate with a video game force multiplier algorithm?
It was an equation that I came up with, since I saw a whole bunch of people complaining about how bad CR is in 5e D&D, and my equation would be a lot better for if someone wanted to use it to balance their game.
I was also inspired by some YouTube videos by Spirit Of The Law, who made some Age of Empires videos in which he used a mathematical equation intended for real warfare in order to estimate the relative strengths of different armies. The problem with that equation was that it assumes that, as the units are damaged, they get weaker, which is not the case in Age of Empires.
I was really surprised that it seemed like no one had come up with an equation like that before.
Yep. BTW, the military has always had equations assessing the relative strength of force multipliers in various tactical situations. You'll never see them, tho. Why declassify them to give your enemy an advantage?
I say the girls win. That's my call because I'd estimate the average guy thinks he is 500% more effective in a fight than he actually is. The average guy has never been in a fight and has no idea how to actually fight but thinks he could take anybody. I think fighting 2 people at once he takes the L.
It feels kind of weird that the OP thinks that we could accurately vote on this. Like others have said too many variables.
It depends on a multitude of variables that I don't feel like getting into right now.
2 against 1? It’s a no brainer. 1 scratches his eyes out while the other gives him a good swift kick in the nuts.
Id say 90% of the time the guy beats both of them up. He's gonna be too strong and hit too hard. Their hits wont affect him and he will really hurt them when he lands.
Well all they have to do is kick the guy in nut, ouch it's all over down on his knees then whale on face till lights out.the reason I say this dang women can scrap,have seen some of the videos? just saying from hard rock dude
Two woman bounty hunter teams (with concealed hand cuffs) train for this situation all the time. They have to hit the guy fast in a synchronized way to win. Check YouTube for instructional videos on team take down and restraint.
All the dude needs to do is to bitch slap the average girls and floor them onto the floor and then the dude would win.