On your part, this statement shows very weak thinking. Your supposition is that I would gladly show any dumb ass my work to gratify my ego. Well, after tutoring all my college friends in advanced calculus, I am tired of helping people who have already given up.
I will make an exception here to show you my work. But this does not mean you are off the hook. I am still expecting you to demonstrate superior mathematical abilities that are at a level of 90% of my own.
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The trick to this infinite recursion expression is to recognize that because it is a geometric series, of sorts, the infinite limit of the entire series without the first term is ½(y),
making the original expression equivalent to 1/2x + ½(y) = y.
Solving, we get,
1/2x = y - y/2
1/2x = y/2
1/x = y
So, x = 1/y.
Now my friend, I never said you were dumb. But, I have serious doubts. Your go. Where's the beef?
Go away you little toad troll. I could care less what the fuck you think. My superior intellect was proven by posing the question in the first place. And you can't call google "your work". I am done with you because you now bore me.
I'm On A Higher Level, But No One Recognizes It
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Nope it is an actual equation. A very difficult one, but real. An infinite recursive series equation.
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MissileExpert
4 years ago
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chuy
4 years ago
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x=1/y
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jethro
4 years ago
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Show your work.
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MissileExpert
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To demonstrate you are worthy of my explanation, you must first show that your IQ is at least 90% of mine.
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jethro
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The fact that you can't answer my question shows that my IQ is 150% greater than yours. Just give it up.
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MissileExpert
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On your part, this statement shows very weak thinking. Your supposition is that I would gladly show any dumb ass my work to gratify my ego. Well, after tutoring all my college friends in advanced calculus, I am tired of helping people who have already given up.
I will make an exception here to show you my work. But this does not mean you are off the hook. I am still expecting you to demonstrate superior mathematical abilities that are at a level of 90% of my own.
------------------------
The trick to this infinite recursion expression is to recognize that because it is a geometric series, of sorts, the infinite limit of the entire series without the first term is ½(y),
making the original expression equivalent to 1/2x + ½(y) = y.
Solving, we get,
1/2x = y - y/2
1/2x = y/2
1/x = y
So, x = 1/y.
Now my friend, I never said you were dumb. But, I have serious doubts. Your go. Where's the beef?
--
jethro
4 years ago
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Go away you little toad troll. I could care less what the fuck you think. My superior intellect was proven by posing the question in the first place. And you can't call google "your work". I am done with you because you now bore me.
Okie dokie then