On your part, this statement shows very weak thinking. Your supposition is that I would gladly show any dumb ass my work to gratify my ego. Well, after tutoring all my college friends in advanced calculus, I am tired of helping people who have already given up.
I will make an exception here to show you my work. But this does not mean you are off the hook. I am still expecting you to demonstrate superior mathematical abilities that are at a level of 90% of my own.
------------------------
The trick to this infinite recursion expression is to recognize that because it is a geometric series, of sorts, the infinite limit of the entire series without the first term is ½(y),
making the original expression equivalent to 1/2x + ½(y) = y.
Solving, we get,
1/2x = y - y/2
1/2x = y/2
1/x = y
So, x = 1/y.
Now my friend, I never said you were dumb. But, I have serious doubts. Your go. Where's the beef?
I'm On A Higher Level, But No One Recognizes It
↑ View this comment's parent
← View full post
Can you even solve this?, looks like you just threw numbers out there.
--
jethro
4 years ago
|
pl
Comment Hidden (
show
)
Report
0
0
Nope it is an actual equation. A very difficult one, but real. An infinite recursive series equation.
--
MissileExpert
4 years ago
|
pl
Comment Hidden (
show
)
Report
0
0
-
chuy
4 years ago
|
pl
Comment Hidden (
show
)
Report
0
0
x=1/y
--
jethro
4 years ago
|
pl
Comment Hidden (
show
)
Report
0
0
Show your work.
--
MissileExpert
4 years ago
|
pl
Comment Hidden (
show
)
Report
1
1
To demonstrate you are worthy of my explanation, you must first show that your IQ is at least 90% of mine.
--
jethro
4 years ago
|
pl
Comment Hidden (
show
)
Report
0
0
The fact that you can't answer my question shows that my IQ is 150% greater than yours. Just give it up.
--
MissileExpert
4 years ago
|
pl
Comment Hidden (
show
)
Report
0
0
See More Comments =>
On your part, this statement shows very weak thinking. Your supposition is that I would gladly show any dumb ass my work to gratify my ego. Well, after tutoring all my college friends in advanced calculus, I am tired of helping people who have already given up.
I will make an exception here to show you my work. But this does not mean you are off the hook. I am still expecting you to demonstrate superior mathematical abilities that are at a level of 90% of my own.
------------------------
The trick to this infinite recursion expression is to recognize that because it is a geometric series, of sorts, the infinite limit of the entire series without the first term is ½(y),
making the original expression equivalent to 1/2x + ½(y) = y.
Solving, we get,
1/2x = y - y/2
1/2x = y/2
1/x = y
So, x = 1/y.
Now my friend, I never said you were dumb. But, I have serious doubts. Your go. Where's the beef?
Okie dokie then